4. Calculate the molar mass of Fe2(SO4)3. Then calculate the mass of iron(III) sulfate of 4.05X1023 formula units. Answer: __269g Fe2(SO4)3_​

Respuesta :

Answer:

399.88 [tex]\frac{4.05*10^{23} }{6.022*10^{23} }[/tex] =269

Explanation:

399.88 is the molar mass of iron(III) sulfate.

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