sydc3 sydc3
  • 11-09-2017
  • Mathematics
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What is v^4-1 simplified

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bminesy2748
bminesy2748 bminesy2748
  • 11-09-2017
The answer is:
(v-1)(v+1)(v^2+1)
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jdoe0001 jdoe0001
  • 12-09-2017
[tex]\bf \textit{difference of squares} \\ \quad \\ (a-b)(a+b) = a^2-b^2\qquad \qquad a^2-b^2 = (a-b)(a+b)\\\\ -------------------------------\\\\ v^4-1\implies v^4-1^4\implies (v^2)^2-(1^2)^2\implies \underline{(v^2-1^2)}(v^2+1^2) \\\\\\ \underline{(v-1)(v+1)}(v^2+1^2)[/tex]
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